Thread 사용 중, ValueError: signal only works in main thread 오류
조회수 2135회
Thread 과 pytchat 을 이용하여 유튜브 라이브 채팅을 불러옴과 동시에, 다른 일을 수행하고 싶습니다.
def chat_get():
global ytloc
ytloc="https://www.youtube.com/watch?v=GoXPbGQl-uQ"
print(ytloc)
chat = pytchat.create(video_id=ytloc)
while True:
if chat.is_alive():
for c in chat.get().sync_items():
print(f"{c.datetime} [{c.author.name}] {c.message}")
time.sleep(1)
temp=Thread(target=chat_get)
temp.start()
오류는 다음과 같이 나오는 데, 어떻게 해결해야할 지 모르겠습니다..
Exception in thread Thread-1:
Traceback (most recent call last):
File "C:\Users\th070\AppData\Local\Programs\Python\Python38-32\lib\threading.py", line 932, in _bootstrap_inner
self.run()
File "C:\Users\th070\AppData\Local\Programs\Python\Python38-32\lib\threading.py", line 870, in run
self._target(*self._args, **self._kwargs)
File "C:\Users\th070\Desktop\youtube_livechat_viewer\live_viewer.py", line 28, in chat_get
chat = pytchat.create(video_id=ytloc)
File "C:\Users\th070\AppData\Local\Programs\Python\Python38-32\lib\site-packages\pytchat\core\__init__.py", line 7, in create
return PytchatCore(_vid, **kwargs)
File "C:\Users\th070\AppData\Local\Programs\Python\Python38-32\lib\site-packages\pytchat\core\pytchat.py", line 89, in __init__
signal.signal(signal.SIGINT, lambda a, b: self.terminate())
File "C:\Users\th070\AppData\Local\Programs\Python\Python38-32\lib\signal.py", line 47, in signal
handler = _signal.signal(_enum_to_int(signalnum), _enum_to_int(handler))
ValueError: signal only works in main thread
-
(•́ ✖ •̀)
알 수 없는 사용자
1 답변
-
from multiprocessing import Pool from threading import Thread import signal def f(x=555): def handler(num, f): print("SIGNAL") try: signal.signal(signal.SIGINT, handler) signal.raise_signal(signal.SIGINT) print(x) return x*x except Exception as e: print(e) #signal only works in main thread return 1 if __name__ == '__main__': try: #멀티프로세싱 with Pool(5) as p: t = p.map(f, [1, 2, 3]) print(t) except Exception as e: print(e) try: #쓰레드 q = Thread(target = f) q.start() except Exception as e: print(e)SIGNAL 1 SIGNAL 2 SIGNAL 3 [1, 4, 9] signal only works in main thread말그대로 signal 은 메인스레드에서만 실행가능합니다. 병렬처리하려는것을 스레드로 옮기거나 pychat 을 멀티프로세싱으로 돌려주세요
댓글 입력