 ## DES 전문가 계십니까?

##### 조회수 225회

DES공부하다가 리차드의 초기치환법이라는게 나왔는데 도통 이해할 수가 없습니다;; 너무 무리한 부탁인건 알지만 원리 좀 설명해 주시면 감사하겠습니다;; 진짜 눈물 날것 같습니다ㅠㅠㅠ;;

``````private void des( int[] inInts, int[] outInts, int[] keys )
{
int fval, work, right, leftt;
int round;
int keysi = 0;

leftt = inInts;
right = inInts;

work   = ((leftt >>  4) ^ right) & 0x0f0f0f0f;
right ^= work;
leftt ^= (work << 4);

work   = ((leftt >> 16) ^ right) & 0x0000ffff;
right ^= work;
leftt ^= (work << 16);

work   = ((right >>  2) ^ leftt) & 0x33333333;
leftt ^= work;
right ^= (work << 2);

work   = ((right >>  8) ^ leftt) & 0x00ff00ff;
leftt ^= work;
right ^= (work << 8);
right  = (right << 1) | ((right >> 31) & 1);

work   = (leftt ^ right) & 0xaaaaaaaa;
leftt ^= work;
right ^= work;
leftt  = (leftt << 1) | ((leftt >> 31) & 1);

for ( round = 0; round < 8; ++round )
{
work   = (right << 28) | (right >> 4);
work  ^= keys[keysi++];
fval   = SP7[ work         & 0x0000003f ];
fval  |= SP5[(work >>  8) & 0x0000003f ];
fval  |= SP3[(work >> 16) & 0x0000003f ];
fval  |= SP1[(work >> 24) & 0x0000003f ];
work   = right ^ keys[keysi++];
fval  |= SP8[ work         & 0x0000003f ];
fval  |= SP6[(work >>  8) & 0x0000003f ];
fval  |= SP4[(work >> 16) & 0x0000003f ];
fval  |= SP2[(work >> 24) & 0x0000003f ];
leftt ^= fval;
work   = (leftt << 28) | (leftt >> 4);
work  ^= keys[keysi++];
fval   = SP7[ work         & 0x0000003f ];
fval  |= SP5[(work >>  8) & 0x0000003f ];
fval  |= SP3[(work >> 16) & 0x0000003f ];
fval  |= SP1[(work >> 24) & 0x0000003f ];
work   = leftt ^ keys[keysi++];
fval  |= SP8[ work         & 0x0000003f ];
fval  |= SP6[(work >>  8) & 0x0000003f ];
fval  |= SP4[(work >> 16) & 0x0000003f ];
fval  |= SP2[(work >> 24) & 0x0000003f ];
right ^= fval;
}

right  = (right << 31) | (right >>> 1);
work   = (leftt ^ right) & 0xaaaaaaaa;
leftt ^= work;
right ^= work;
leftt  = (leftt << 31) | (leftt >>> 1);
work   = ((leftt >>>  8) ^ right) & 0x00ff00ff;
right ^= work;
leftt ^= (work << 8);
work   = ((leftt >>>  2) ^ right) & 0x33333333;
right ^= work;
leftt ^= (work << 2);
work   = ((right >>> 16) ^ leftt) & 0x0000ffff;
leftt ^= work;
right ^= (work << 16);
work   = ((right >>>  4) ^ leftt) & 0x0f0f0f0f;
leftt ^= work;
right ^= (work << 4);
outInts = right;
outInts = leftt;
}
``````

## 답변을 하려면 로그인이 필요합니다.

Hashcode는 개발자들을 위한 무료 QnA 사이트입니다. 계정을 생성하셔야만 답변을 작성하실 수 있습니다.

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